Question

Find the partial fractions of 4x+3/(x^2)(x^2+1)​

Answer 1

Answer:

The partial fraction is:

$\dfrac{A}{x}+\dfrac{B}{x^2}+\dfrac{Cx+D}{x^2+1}$

Step-by-step explanation:

Given question is:

$\dfrac{4x+3}{x^2(x^2+1)}$

Then the partial fraction of the given function can be written as:

$\dfrac{4x+3}{x^2(x^2+1)}=\dfrac{A}{x}+\dfrac{B}{x^2}+\dfrac{Cx+D}{x^2+1}$