Question

Find the particular and general solution of the equations:
x2dy+(y–1)dx=0

Answer 1

Answer:

${x}^{2} dy + (y - 1)dx = 0 \\ \\ {x}^{2} dy = - (y - 1)dx \\ \\ \frac{dy}{y - 1} = - \frac{dx}{ {x}^{2} } \\ \\ integration \: \: \: both \: \: \: side = > \\ \\ ln(y - 1) = \frac{1}{x} + c$