Question

Find the particular and general solution of the equations:

(2x–1)dx=(y+1)dy
y=0, x=5

Answer 1

Answer:

solved

Step-by-step explanation:

(2x–1)dx=(y+1)dy

∫(2x–1)dx =∫(y+1)dy

y²/2 + y = x² - x + k  , k = constant

y=0, x=5 , k = - 20

general solution     →    y²/2 + y = x² - x + k

particular  solution  →   y²/2 + y = x² - x -20