Find the pattern
1,5,17,63,161_,_
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4 = 1 + 3 which is ( 3 ^0 + 3^1 )
12 = 3 + 9 which is ( 3^1 + 3^2 )
36 = 9 + 27 which is ( 3^2 + 3^3 )
108 = 27 + 81 which is ( 3^3 + 3^4 )
( 3^4 + 3^5) = ( 81 + 243 ) = ( 324 )
( 3^5 + 3^6 ) = ( 243 + 729 ) = ( 972 )
( 3^6 + 3^7 ) = ( 729 + 2187 ) = ( 2916 )
(up to)
( 3^n + 3^(n+1) ) where in this case, “ n ” is any Integer greater than 6.
1, 5, 17, 53, 161, 324, 972, 2916 and so on.
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