Question

Find the peak value of an AC sine wave of rms value of 115V.

Answer 1

Given that,

rms value of AC voltage = 115 V

Peak value of AC voltage :

Peak value of AC voltage is equal to the rms value multiply by the root 2.

We need to calculate the peak value of AC voltage

Using formula of rms value

$V_{rms}=\dfrac{V_{p}}{\sqrt{2}}$

$V_{p}=V_{rms}\times\sqrt{2}$

Where, $V_{rms}$ = rms voltage

$V_{p}$ = peak voltage

Put the value into the formula

$V_{p}=115\times\sqrt{2}$

$V_{p}=162.6\ V$

Hence, The peak value of AC sin wave is 162.6 V.