Question

Find the pedal equation of the parabola y^2=4ax with respect to the vertex

Answer 1

Let S be the focus and the line l be the directrix. Draw SZ perpendicular to the line l. Take O as the midpoint of SZ. Now take O as the origin. Take OS produced as X-axis and the perpendicular to OS at O as Y-axis. Let SZ = 2a. The OS = a. Therefore, S=(a,0)

Now let P(x,y) be any point on the curve. Join PS and draw PM perpendicular to the line l and PN perpendicular to x-axis

Then by definition of the parabola, PS = PM. By distance formula, PS = √ { (x-a)^2 + y- 0)^2} and PM = NZ = x + a

Hence squaring we have (x-a)^2 +y^2 = (x+a)^2 or x^2 -2ax + a^2 + y^2 = x^2 + 2ax + a^2 i.e., y^2 = 4ax

Hence the equation of the parabola is y^2 = 4ax

Answer 2

Answer:

it is a rong answer

the first and a couple are in the same place