Find the percentage change in the weight of an object if it is taken to height of
64/11 kmabove the
surface of earth
surface of earth (R = 6400 km)
(A)1/11
(B)2/11
(C)3/11
(D)4/11
send correct answer or else I ll report u
and answer is not 0.5
Answers
Answered by
1
4/11 is the correct answer
Answered by
0
Answer:
Here d= 32 km R= 6400 km
weight of body at depth d is mg`
=mg(1-d/R)%
decrease in weight =( mg- mg`)/mg × 100= 32 / 6400×100 = 0.5%.
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