Question

find the percentage composition of constituent green vitriol crystal also find the mass of iron and the water of crystallization in 4.54kg of the crystals​

Answer 1

Answer:

Atomic mass of Fe=56 and S=32, O=16

Mass of crystal=4.54kg

percentage=$\frac{Mass of the element in 1mole of compound}{Molar mass of the compound} *100$

Molar mass of $FeSO_{4} .7H_{2} O$=1*(56)+1*(32)+14*(1)+11*(16)

                                                                        =56+32+14+176

                                                                        =278g mol

Percentage of Fe=$\frac{56}{278} *100=20.14%$

Percentage of S=$\frac{32}{278} *100=11.51%$

Percentage of H=$\frac{14}{278} *100=5.04%$

Percentage of O=$\frac{176}{278} *100=63.31%$

278kg green vitriol=56 kg iron

4.54 kg green vitriol=x

x=$\frac{56*4.54}{278} =0.915kg$

mass of 7H2O in 278 kg green vitriol=7*18=126kg

4.54 kg green vitriol=y

y=$\frac{126*4.54}{278} =2.058kg$