Question

Find the percentage composition of constituent green vitriol crystals

Answer 1

Answer:

Molar mass of =1*(56)+1*(32)+14*(1)+11*(16) =56+32+14+176. =278g mol. Percentage of Fe= Percentage of S= Percentage of H= Percentage of O= 278kg green vitriol=56 kg iron. 4.54 kg green vitriol=x. x= mass of 7H2O in 278 kg green vitriol=7*18=126kg. 4.54 kg green vitriol=y.