find the percentage composition of MgSO4 .7 H²O
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Answered by
0
Answer:
MgSO4. 7H2O
MM=24.31+32.06+4(16)+7(18.02)
=246.51g/mol
percent h2o. = 7(18.02g/mol) ento 100
246.51g/mol
= 51.17 Percent H2o
Answered by
0
Answer:
MgSO4.7H20
24+32+(4×8)+7[(2×1)+8]
=24+32+32+70
=158 amu
Percentage composition of Mg = (158÷24)×100 =37.92 %
Percentage of Sulphur = (158÷32)×100=49.37 %
Percentage of Hydrogen =
(158÷2)×100= 79%
Percrntage of Oxygen =
(158÷16)×100=16.35%
.........
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