Question

Find the percentage composition of na, s and o in sodium thiosulphate

Answer 1

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$\huge\red{Formula of sulphur thiosulphate}$

Na2S2O3

Molar mass of Na2S2O3 = 23×2 + 32×2 + 16×3 = 46 + 64 + 48

Molar mass of Na2S2O3 = 158g/mol

$\huge\blue{Percentage composition :- }$

Mass contributed by Na2 = 23×2= 46

Mass contributed by S2 = 32×2=64

Mass contributed by O3 = 16×3=48

Now ........

Percentage of Na2 = mass contributed by Na2/ Molar mass of Na2S2O3 ×100

Percentage of Na2 = 46/158×100

$\huge\purple{Percentage of Na2 = 29percent }$

Percentage of S2 = 64/158×100

$\huge\green{Percentage of S2= 40percent}$

Percentage of O3 = 48/158×100

$\huge\red{Percentage of O3 = 30 percent }$

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Answer 2

Explanation:

29.11% Na 40.5% S and 30.39% O