Question

Find the percentage composition of sodium in sodium sulphate solution.

Answer 1

molar mass of sodium sulphate=46+32+64=142
Na2SO4

% of Na =46/142×100=32 .2

Answer 2

AnswEr:

percentage composition of sodium in Sodium sulphate is 32.66%

ExplanaTion:

Given Solution :

• Sodium sulphate.
• Chemical formula = $\sf{Na_{2} SO_{4}}$

Now, we have to find percentage composition of sodium in the given Solution.

For finding percentage composition, we've to find its molecular mass.

Known quantities :

• Na = 23 g
• S = 32 g
• O = 16 g

Molecular mass = 23(2) + 32 + 16(4)

: $\implies$ Molecular mass = 46 + 32 + 64

$\therefore$ Molecular mass of sodium sulphate is 142 g

$\rule{200}2$

Now, let's find percentage composition of Sodium or Na.

: $\implies$ Percentage composition of sodium = $\sf{23}{100}\: \times 142}$

: $\implies$ Percentage composition of sodium = 32.66%

Hence, percentage composition of sodium in Sodium sulphate is 32.66%