Find the percentage composition of the following:
Percentage of S in Al2(SO4)3
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Answered by
2
Answer: 28.11%
% by mass =
mass of component /total mass × 100 %
Mass of 2 Al atoms = 2 Al atoms × 26.98 u /1 Al atom
= 53.96 u.
Mass of 3 S atoms = 3 S atoms × 32.06 u /1 S atom
= 96.18 u
Mass of 12 O atoms = 12 O atoms × 16.00 u /1 O atom
= 192.0 u
Mass of 1 Al₂(SO₄)₂ formula unit = (53.96 + 96.18 + 192.0) u = 342.1 u
% of Al =
mass of Al /total mass × 100 %=
53.96 u /342.1 u × 100 %
=15.77 %
% of S = mass of S /total mass × 100 % =
96.18 u /342.14 u × 100 %
=28.11 %
% of O =
mass of O /total mass × 100 % =
192.0 u /342.14 u × 100 % =
56.12 %
Answered by
0
Answer:S=16
Explanation:idont sure about this
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