Question

Find the percentage composition of the following:
Percentage of S in Al2(SO4)3

Answer 1

Answer: 28.11%

% by mass =  

mass of component /total mass  × 100 %

Mass of 2 Al atoms = 2 Al atoms ×  26.98 u /1 Al atom

= 53.96 u.

Mass of 3 S atoms = 3 S atoms ×  32.06 u /1 S atom

= 96.18 u

Mass of 12 O atoms = 12 O atoms ×  16.00 u /1 O atom

= 192.0 u

Mass of 1 Al₂(SO₄)₂ formula unit = (53.96 + 96.18 + 192.0) u = 342.1 u

% of Al =  

mass of Al /total mass  × 100 %=  

53.96 u /342.1 u × 100 %

=15.77 %

% of S =  mass of S /total mass × 100 % =  

96.18 u /342.14 u  × 100 %

=28.11 %

% of O =  

mass of O /total mass  × 100 % =  

192.0 u /342.14 u  × 100 % =

56.12 %

Answer 2

Answer:S=16

Explanation:idont sure about this