Question

find the percentage decreament in the weight of a body when taken to height equal to height of 16 km above the surface of earth​

Answer 1

Answer:

⇒ 1 %

Explanation:

We know,

By formula :-

$g_{h}$ = g( 1 - $\frac{2h}{R}$ )

or,

$g_{h}$ = g - $\frac{2hg}{R}$

Multiplying with m on both sides , we get :-

$mgh^{'}$ = mg - $\frac{2mgh}{R}$

So,

% increase in weight =  $\frac{mg - mg_{h} }{R}$ * 100

$\frac{2mgh}{R}  = m(\frac{g-g_{h} }{g} ) * 100$

After cancelling 'm' from both sides, we get :-

$\frac{2h}{R}  = \frac{g-g_{h} }{g} * 100$

⇒ $\frac{2*32}{6400} *100$

⇒ 1 %

Thanks !

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