Physics, asked by revatirelekar, 6 months ago

find the percentage error in kinetic energy of a body having mass 60.0+-0.3g moving with a velocity 25.0+-0.1cm/s​

Answers

Answered by abhi569
20

Answer:

1.3%

Explanation:

% errors = |error/quantity| 100%

          = [ | 0.3/60 | + 2|0.1/25 | ] * 100%

          = [ 0.005 + 0.008 ] * 100%

          = [ 0.013 ] * 100%

          = 1.3 %

Kinetic energy = (1/2) mv^2

 So, error = |mass error/mass| + 2|error/velocity|

As the exponent of velocity is 2, we wrote 2 in multiplication for errors. *using properties.

Similar questions