Physics, asked by vaibhav1673, 11 months ago

Find the percentage error in kinetic energy of a body of mass 60.​

Answers

Answered by pallavishilpi
14

%Uncertainty in mass= 0.3/60 x100 = 0.5%

% uncertainty in mass = 0.1/25 = 0.4%

K.E= 1/2 mv^2

K.E = m+ 2V

K.E= 0.5 + 2 x 0.4

K.E= 0.5 + 0.8

K.E= 1.3% uncertainty.

Answered by CarliReifsteck
0

Answer:

The kinetic energy is 2.7 %.

Explanation:

Suppose the percentage error of the velocity of the object is 1.2 and mass of the object is 60 kg.

The percentage error of the mass of the object is 0.3.

We need to calculate the percentage of the kinetic energy

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

K.E=m+2\times v

Where, m = mass of the object

v = velocity of the object

Put the value into the formula

K.E=0.3+2\times 1.2

K.E=2.7\%

Hence, The kinetic energy is 2.7%.

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