Question

find the percentage error of heat dissociate in a resistance H=I2Rt percentage error in current= 2% resistance=3% time=1%​

Answer 1

Answer:

Q=I

2

Rt

⇒

Q

ΔQ

=

I

2ΔI

+

R

ΔR

+

t

Δt

⇒

Q

ΔQ

×100=2(2)+1+1

⇒

Q

ΔQ

×100=6%

Explanation:

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