Question

Find the percentage increase in KE of a body. it's momentum is increased by 50% .

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Answer 1

Explanation:

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Answer 2

TO FIND :

The percentage increase in KE of a body.

SOLUTION :

Let, $P_i$ = Initial momentum

According to the given information,

→ $P_f = P_i + 50 \% P_i$

→ $P_f = P_i + \dfrac {500}{100} P_i$

→ $P_f = P_i + 0.5 P_i$

→ $P_f = 1.5 P_i$

$KE = \dfrac {p^{2}}{2m}$ ............ $KE \propto p^{2}$

$KE_f = (1.5)^{2} \times KE_i$

$2.5 \times KE_i$

$\therefore \Delta KE = KE_f - KE_i$

→ $2.25 KE_i - KE_f$

→ $1.25 KE_i$

→ $\Delta KE \times 100 = 1.25 \times 100 \% KE_f$

→ $125 \% KE_i$

$\therefore$ The percentage increase in KE of a body is 125$\% KE_i$.