Find the percentage increase in the area of a rectangle,if there is an increase of 10% in both length and breadth of the rectangle
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let the length of a rectangle = l
breadth = b
area,a = length ×breadth = lb
l,b increased by 10%
l1 = l*(1+10%) = 1.1l
b1 = b*(1+10%) = 1.1b
new area a1 = l1* b1 = 1.1l×1.1b = 1.21lb
= 1.21a =(1+21%)a
area increased by 21%
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answer is 20 percentage blah!!
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