Question

find the percentage increase in the area of a triangle if its each side is doubled

Answer 1

the question is not clear

Answer 2

s =a+b+c/2
A=√s(s-a)(s-b)(s-c)

now sides of triangle are 2a , 2b and 2c

s1= 2a+2b+2c/2
=>s1 =2(a+b+c)/2
=>s1 =2s

A1 =√2s(2s-2a)(2s-2b)(2s-2c)
=>A1=4×√s(s-a)(s-b)(s-c)
=>A1=4A

PERCENTAGE INCREASE =A1-A/A×100
                                             =4A-A/A×100
                                              =3A/A×100
                                               =3×100
                                                   =300%