Question

Find the percentage ionic character of a molecule a b if electronegativity x is equals to 1.5 x 20 equals to 2.5

Answer 1

Answer:

Linus Pauling proposed an empirical relationship which relates the percent ionic character in a bond to the electronegativity difference Δχ

.

Percent ionic character =(1−e−(Δχ/2)2)×100

But I'd like to correct the definition of percent ionic character in your question using dipole moment μ

(not Observed value of ionic character):

Percent ionic character = μobservedμcalculated

×100%

Where μcalculated

is calculated assuming a 100% ionic bond.

Explanation: