Question

find the percentage mass of water in Epsom salt MgSo4 . 7H2O​

Answer 1

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Formula of EPSOM salt = MgSO4.7H2O

molecular mass of MgSO4.7H2O = atomic mass of Mg + atomic mass of S + 4 × atomic mass of O + 7 { 2 × atomic mass of H + atomic mass of O }

= 24 + 32 + 4× 16 + 7{ 2 × 1 + 16 } g/mol

= (24 + 32 + 64+ 126 ) g/mol

= 246 g/mol

molecular mass of total water = 7 × ( 2× atomic mass of H + atomic mass of O )

= 7 × 18 = 126 g/mol

now ,

% mass of H2O in EPSOM salt = {total molar mass of H2O/molar mass of Epsom salts }× 100

= {126/246 } × 100

= 12600/246

= 51.21 %

Hope it HELPS....❤

Answer 2

Answer:

51.21%

Explanation:

Atomic mass of Epsom salt (MgSo4.7H2O)

24+32+(4×16)+7{(2×1)+16}

=56+64+126

=246u

Atomic mass of water in Epsom salt

=7{(2×1)+16}

=126u

Therefore,

Percentage of water in Epsom salt=

(126/246)×100

=51.21% (ANS)

I hope it helps.

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