Question

find the percentage of co2 present in dolomite & also find the volume of co2 gas that 1 gram of the sample can liberate from dilute acid at ntp​

Answer 1

Answer:

Explanation:

CaCO  

3

​  

⇌CaO+CO  

2

​  

 

One mole of calcium carbonate on decomposition gives one mole of carbon dioxide.

The molecular weight of calcium carbonate is 100 g/mol.

10 g calcium carbonate corresponds to 0.1 mol. It on decomposition will give 0.1 mol of carbon dioxide. But limestone is only 90% pure. Hence, 0.09 mol of carbon dioxide will be obtained.

1 mole of carbon dioxide occupies 22.4 L at STP.

Hence, 0.09 mol of carbon dioxide will occupy 0.09×22.4=2.016 L.