Question

find the percentage of composition of Ammonium Nitrate (N=14,H=1,O=16)​

Answer 1

Answer:

Percent composition of N is 28g80g×100%=35% .

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Answer 2

Answer:

2×14g+4×1g+3×16g=80g

The mass of 1 mol of NH4NO3 is 80g.

2×14g=28g

The mass of N is 28g.

Percent composition of N is 28g80g×100%=35%.

4×1g=4g

The mass of H is 4g.

Percent composition of H is 4g80g×100%=5%.

3×16g=48g

The mass of O is 48g.

Percent composition of O is 48g80g×100%=60%

Explanation:

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