Question

Find the percentage of (Cr2O7)- in (NH4)2CR2O7.​

Answer 1

Answer:

85.71%

Explanation:

Answer 2

Answer:

The percentage composition of Cr2O7 in (NH4)2Cr2O7 is 85.7143%

Explanation:

The molecular mass of (NH4)2Cr2O7 = [{14+(1×4)}2] +

(52×2) + (16×7)

= [18×2] + 104 + 112

= 252

The molecular mass of Cr2O7 = (52×2) + (16×7)

= 216

In 252 gram (NH4)2Cr2O7 the amount of Cr2O7=216 gram

In 1 gram (NH4)2Cr2O7 the amount of Cr2O7 = 216/252 g

In 100 gram (NH4)2Cr2O7 the amount of Cr2O7

= 0.857×100 gram

= 85.7 gram

So, the percentage composition of Cr2O7 in (NH4)2Cr2O7 is 85.7%