Find the percentage of each element in a. Potassium chlorate, KClO3 (K= 39, Cl= 35.5, O = 16) b. Sodium carbonate Na2CO3 (Na =23, C =12, O= 16)
Answers
Answered by
0
Explanation:
Relative molecular mass of KClO
3
=39.09+35.5+(3×16)
=122.59g
122.59gKClO
3
contains 39.09gK
Hence, 100gKClO
3
contains
=
122.59
100×39.09
=31.9g
122.59gKClO
3
contains 35.5gCl
Hence, 100gKClO
3
contains
=
122.59
100×35.5
=28.9g
122.59gKClO
3
contains 48gO
Hence, 100gKClO
3
contains
=
122.59
100×48
=39.1g
The percentage of K,Cl and O in KClO
3
are 31.9%,28.9% and 39.1% respectively.
Similar questions