Find the percentage of Magnesium in Magnesium hydroxide . [Mg=24, H=1, O=16]
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Answer:
Magnesium Hydroxide = Mg(HO) 2
Total Mass = 24+(1+16) *2
=24+17*2
=24+17*2=24+34
=24+17*2=24+34=58.
Mass of Mg in Mg(HO) 2= 24.
So percentage of Magnesium=
24/58*100%
24/58*100%=41.38%
Thus, Percentage of Magnesium= 41.38% Answer.
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