find the percentage of phosphorous in calcium phosphate Ca3(PO4)2 Ca=40 p=31 O=16
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Molecular formula of calcium phosphate is Ca3(PO4)2
Total Mass of Calcium Phosphate = 40*3 + 31*2 + 16*8
= 120 + 62 + 128
= 310 g
Mass of phosphorus = 31 g
Therefore, % of phosphorus in calcium phosphate = (31/310 *100)
= 10 %
Hence, the answer is 10%.
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