Question

Find the perfect cube of 1800

Answer 1

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The exponents are 2,3, and 2. To make a perfect cube, we need to make them divisible by 3 90 is also divisible by 3). So, we need to divide it by 3^2*5^2 = 225. This is assuming that you want to divide 1800 by the smallest natural number to get a perfect cube.

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Answer 2

Answer:

$\boxed{ hello \: mate }$

The exponents are 2,3, and 2. To make a perfect cube, we need to make them divisible by 3 90 is also divisible by 3). So, we need to divide it by 3^2*5^2 = 225. This is assuming that you want to divide 1800 by the smallest natural number to get a perfect cube.

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