Question

find the perimeter
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Answer 1

Step-by-step explanation:

AC=10 BD=8

AE=CE=5

BE=DE=4

To find AB,AD,BC,CD we need to use Pythagoras theorem for each triangle

for ∆AEB

AB=✓25+16=√41=AD=BC=CD

because all sides of rhombus are equal

so Perimeter= 4√41

Answer 2

Answer:

perimeter of rhombus=4√41 unit

Step-by-step explanation:

The diagonals of a rhombus bisect at right angle

So BE=BD/2=8/2=4 unit

EC =AC/2=10/2= 50unit

and ∠BEC=90°

Thus in the ΔBEC

BC=√(BE²+EC²

=√4²+5²

=√41

Thus side =√41

Hence perimeter of rhombus=4√41 unit