Question

find the perimeter and are of a rectangle whose length is 8m and breadth is 11 m
pls guys​

Answer 1

Answer:

The answer will be:

Perimeter = 38m

Area = 88m^2.

Step-by-step explanation:

Perimeter of rectangle = 2(l+b)

Thus, perimeter = 2(8 +11)

= 2 × 19

= 38 m

Area of rectangle= lb

= 8 × 11

= 88 m^2

That's all.

Answer 2

Given:

• Length of Rectangle = 8m
• Breadth of Rectangle = 11m

To Find:

• The Perimeter and Area of Rectangle

Solution:

❂ $\bold{Perimeter\;of\; Rectangle = 2(l+b)}$

$→\;{\sf{2(8+11)}}$

$→\;{\sf{2(19)}}$

$➝\;{\bf{38m}}$

❂ $\bold{Area\;of\;Rectangle = l×b}$

$→\;{\sf{8×11}}$

$➝\;{\bf{88m²}}$

AnSweR:

Perimeter of Rectangle ◕➜ $\Large{\red{\mathfrak{38m}}}$

Area of Rectangle ◕➜ $\Large{\pink{\mathfrak{88m²}}}$

Hope It Helps You ✌️