Question

find the perimeter and are of the figures given below.(π=22/7)​

Answer 1

Answer:

49m is correct answer

Step-by-step explanation:

10+7+10+7

Answer 2

$\mathfrak{{\pmb{{\underline{To~find}}:}}}$

• Area of the shaded region

$\mathfrak{{\pmb{{\underline{Solution}}:}}}$

$\sf Area \: of \: the \: shaded \: region = \pmb{area \: of \: the \: rectangle - area \: of \: the \: semicircle}$

$\sf{{\pmb{{\underline{Area~of~the~rectangle}}:}}}$

• Length = 10m
• Breadth = 7m

$\sf{Area~of~rectangle=l \times b}$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies 10 \times 7}$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies {\blue{\underline{\boxed{\sf{\pmb{70m^{2}}}}}}}}$

$\sf{{\pmb{{\underline{Area~of~the~semicircle}}:}}}$

• Diameter = 7m

$\sf{~~~~~ \therefore Radius = {\pmb{{\dfrac{7}{2}}}} }$

$\sf{Area~of~semicircle={\dfrac{1}{2}} \pi r^{2}}$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies {\dfrac{1}{ \cancel{ \: 2 \: }}} \times {\dfrac{\cancel{22}~~^{11}}{\cancel{~7~}}} \times {\dfrac{\cancel{~7~}}{2}} \times {\dfrac{7}{2}} }$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies 1 \times 11 \times {\dfrac{1}{2}} \times {\dfrac{7}{2}} }$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies 11 \times {\dfrac{7}{4}} }$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies {\dfrac{11 \times 7}{4}} }$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies {\dfrac{77}{4}} }$

$\sf{~~~~~~~~~~~~~~~~~~~~~~~~ \implies {\blue{\underline{\boxed{\sf{\pmb{19.25m^{2}}}}}}}}$

$\therefore\mathfrak{{\pmb{{\underline{Required~answer}}:}}}$

$\sf Area \: of \: the \: shaded \: region = \pmb{area \: of \: the \: rectangle - area \: of \: the \: semicircle} \\ \sf \implies 70 - 19.25 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies \blue{ \underline{ \boxed{ \sf{ \pmb{50.75 {m}^{2} }}}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\therefore \sf Area \: of \: the \: shaded \: region = \blue{ \underline{ \boxed{ \sf{ \pmb{50.75 {m}^{2} }}}}}$