Question

find the perimeter and area​

Answer 1

area equal ten multiple eight equal eighty

Answer 2

Step-by-step explanation:

$in \: triangle .\: we \: have \\ hypotemuse \: and \: perpendicular \\ \\ so \: use \: pythagoras \: theorem \\ \\( h) {}^{2} =( p) {}^{2} + (b) {}^{2} \\ \\ (10) {}^{2} = (8) {}^{2} +( b) {}^{2} \\ \\ (b) {}^{2} = (10) {}^{2} - (8) {}^{2} \\ \\ (b) {}^{2} = 100 - 64 \\ \\ \\ b = \sqrt{36} \\ \\b = 6cm \: \: \\ \\ now \: we \: get \: radius \: of \: the \: semicircle \: \\ \\ area = area \: of \: trieangle \: + area \: of \: semicirle \\ \\ \: \\ 1 \div 2 \times b \times h \\ + 1 \div 2 \times \pi \: r {}^{2} \\ \\ 1 \div 2 \times 6<strong> </strong><strong>plus6</strong> \times 8 + 1 \div 2 \times 22 \div 7 \times 6 \times 6 \\ \\ 48 + 56.57 = 104.57cm {}^{2} \\ \\ perimeter = perimeter \: of \: the \: triangle + perimeter \: of \: semicircle \\ \\ l + b + c \: + \pi \: r \\ \\ 10 + 10+12 + 22 \div 7 \times 6 \\ \\ \\ \\ 32 + 18.85 \\ 50.85cm$