Find the perimeter and area of a rectangle of sides
(a) 5 cm and 9 cm (b) 11 m and 22 m
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Answered by
1
a) p= 2(l+b)
= 2(5+9)
= 2×14
= 28cm
b)p =2(l+b)
= 2(11+22)
= 2×33
= 66m
Answered by
4
Area of Rectangle = L×B
perimeter of Rectangle = 2(L+B)
(a) Area of Rectangle =5×9=45cm²
Perimeter of Rectangle = 2(5+9)
= 28 cm
(b) Area of Rectangle = 11×22
= 242 cm²
Perimeter of Rectangle = 2(11+22)
= 66 cm
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