Question

find the perimeter and area of a rectangle whoes length is 47/15 and bredth is 9/4??????

Answer 1

S O L U T I O N

G I V E N

B E L O W:

Length=
$\frac{47}{15}$
Length =
$\frac{9}{4}$
So perimeter of a rectangle=
$2 \times (x + y)$

$2 \times ( \frac{47}{15} + \frac{9}{4} )$

$\frac{323}{30}$
This is perimeter.

Now its area=
$x \times y$
$\frac{47}{15} \times \frac{9}{4}$

$\frac{141}{20}$
This is the area.