find the perimeter and area of a rectangle whose breadth is 7 cm and diagonal is 25 CM
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The diagonal here acts as the hypotenuse of the two triangles formed by the diagonal.
Using the Pythagores theorem-
(25)² = (7)² + (b)².......( b here represents the length)
625 = 49 + b²
b² = 625-49
= 576
b = 24cm
Perimeter of rectangle is 2 × 24+ 7
= 2 × 31
= 61cm
Area -
24 × 7
= 168cm²
Using the Pythagores theorem-
(25)² = (7)² + (b)².......( b here represents the length)
625 = 49 + b²
b² = 625-49
= 576
b = 24cm
Perimeter of rectangle is 2 × 24+ 7
= 2 × 31
= 61cm
Area -
24 × 7
= 168cm²
ved2728:
I don't understand explain again
Okie
well every angle of the rectangle is 90° right?
The diagonal divides the rectangle into two right angles.
*right triangles
Hence the diagonal here acts as the hypotenuse of both the triangles
To find both area and perimeter we need the length which is missing here
hence by using the Pythagores theorem and taking the missing length as the base we can find out it's length. Once the length is out we can put it in the formula and find out the area and pm
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