Math, asked by robinu81, 7 months ago

Find the perimeter and area of a rectangle whose length is 7.8 cm and breadth is 3.2 cm?

Answers

Answered by kumardeo080
5

Answer:

22 cm and 24.96 cm²

Step-by-step explanation:

Length of the rectangle = 7.8 cm

Breadth of the rectangle = 3.2 cm

So, perimeter of the given rectangle =

2(Length + Breadth)

= 2(7.8+3.2)

= 2×11

= 22 cm

And area of the given rectangle =

Length × Breadth

= (7.8 × 3.2) cm²

= 24.96 cm²

Hence, the perimeter of the given triangle is 22 cm and its area is 24.96 cm²

Hope, it may be helpful, if it solved your problem don't forget to mark as the brainliest.

Answered by bhagathmanoj2905
2

Answer;-

22 cm and 24.96 cm²

Step - By Step - Solution

Length of the rectangle = 7.8 cm

Breadth of the rectangle = 3.2 cm

So, perimeter of the given rectangle =

2(Length + Breadth)

= 2(7.8+3.2)

= 2×11

= 22 cm

And area of the given rectangle =

Length × Breadth

= (7.8 × 3.2) cm²

= 24.96 cm²

Hence, the perimeter of the given triangle is 22 cm and its area is 24.96 cm²

Hope, it may be helpful, if it solved your problem don't forget to mark as the brainliest.

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