Math, asked by Anonymous, 1 month ago

find the perimeter and area of a rectangular Garden with 46 CM length and 56 CM breadth ​

Answers

Answered by Itzkirtihere
6

ur Answer is with attachment.

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Answered by Anonymous
36

Given:

  • The lenght of the rectangular field is 56cm
  • The breadth of the field is 46cm

To Find:

  • The perimeter and the area of the field

Diagram:

Rectangle:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 56 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 46 cm}\end{picture}

Solution:

➱ As we have both the dimensions of the rectangular garden now, let's use suitable formulae to find the perimeter and the area of the garden.

✪ Formula to find the area of a rectangle :

 \:  \:  \:  \:  \dag \:  \:  \: \bigg( \bf \: area _{(rectangle)} = lenght \times breadth \bigg)

Here,

  • The measurement of the length is 56cm
  • The measurement of the breadth is 46cm

Now,

  • Let's substitute the values

{ : \implies} \sf \: Area _{(rectangle)} = lenght \times breadth\\\\

{ : \implies} \sf \: Area _{(rectangle)} = 56cm \times 46cm\\\\

{ : \implies} \sf \: Area _{(rectangle)} = { \boxed{ \pmb{ \frak{2576 {cm}^{2} }}} \bigstar}

  • Henceforth the area of the rectangle is 2576cm²

✪ Formula to find the perimeter of the rectangle :

 \:  \:  \:  \:  \dag \:  \:  \: \bigg( \bf \: perimeter_{(rectangle)} =2( l  +  b) \bigg)

Where,

  • L denotes length
  • B denotes breadth

Here,

  • The measurementof length is 56cm
  • The measurement of the breadth is 46cm

Now,

  • Let's substitute the values

{ : \implies} \sf \: Perimeter  _{(rectangle)} = 2(l + b)\\\\

{ : \implies} \sf \: Perimeter  _{(rectangle)} = 2(56cm + 46cm)\\\\

{ : \implies} \sf \: Perimeter  _{(rectangle)} = 2(102cm)\\\\

{ : \implies} \sf \: Perimeter  _{(rectangle)} = { \boxed{ \pmb{ \frak{204cm}}} \bigstar}

  • Henceforth the perimeter of the rectangle is 204cm

Hence,

  • The perimeter and the area of the rectangle are 204cm and 2576cm² respectively

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More to know:

Related Formulae:

Some related formulas :-

\begin{gathered}\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{{Area}_{(Parallelogram)} = Base \times Hieght} \\ \\ \bigstar \:\sf{{Length}_{(Rectangle)} = \dfrac{Perimetre}{2} - Breadth} \\ \\ \bigstar \: \sf{{Breadth}_{(Rectangle)} = \dfrac{Perimetre}{2} - Length} \\ \\ \bigstar \: \sf{{Length}_{(Rectangle)} = \dfrac{Area}{Breadth}} \\ \\ \bigstar \: \sf{{Breadth}_{(Rectangle)} = \dfrac{Area}{Length}}\end{array}}\end{gathered}

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