Question

Find the perimeter and area of a rectangular
with length 3.4 cm and 2.3 cm. Also find
the perimeter and area
of a square of wide
2.7 cm​

Answer 1

Answer:

perameter of rectangle=2(l+b)

p=2(3.4+2.3)=11.4

area of rectangle=l×b

a= 3.4×2.3=7.82

perameter of square=4×side

p=4×2.7=10.8

area of square=side^2

a=2.7×2.7 =7.29

Answer 2

Answer:

$l = 3.4 \: cm \: \: b = 2.3 \: cm \\ perimeter = 2(l + b) \\ = 2(3.4 + 2.3) \\ = 2 \times 5.7 \\ = 11.4 \: cm \\ area \: = l \times b \\ = 3.4 \times 2.3 \\ = 7.82 \: cm {}^{2} \\ \\ perimeter \: of \: square \: = 4 \times side \\ = 4 \times 2.7 \\ = 10.8 \: cm \\ area \: = (side) {}^{2} \\ = 7.29 \: cm {}^{2}$

HOPE IT HELPED!!!!!⚡