Question

find the perimeter and area of a square whose diagonal is 8root 2
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Answer 1

Answer:

its perimeter is 32 and area 64

Answer 2

formula ,

area of square = (side)*2

perimeter of square = 4 × side

by hypotenuse theorem

(diagonal)*2 = (first side)*2 + (second side)*2

.........let first & second side be x

8√2 = x*2 + x*2

8√2 = 2(x)*2

8√2/2 = x*2

4√2 /√2 = x

4 = x

here your answer,

X = 4 so, side of square is 4 cm

perimeter of square = 4×side

= 4×4

= 16 sq.cm

area of square = (side)*2

= (4)*2

= 16.