Find the perimeter and area of a Whose sides are 52 cm, 56 cm and 60 cm respectively.
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perimeterof trangle is S+S+S=52+56+60=168
herons formula=√s(s-a)s(s-b)s(s-c)
s=a+b+c/2
52+56+60/2=84
areaof traingle =√84(84-52)84(84-56)84(84-60)
√84×32×28×24cmsq
√4×3×7×4×2×2×2×4×7×4×2×3
4×4×7×3×2×2=1334cmsq
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