find the perimeter and area of an equirateral triangle whose height is 12cm.write your answer, correct to two or decimal places
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no sides are there
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Let each side be x.
height=12 cm
In Triangle ABC
From B make one perpendicular and join it to AC at D
Now, AB=x and BD=x/2
Therefore,
(x)^2=(x/2)^2+(12)^2(by pythagoras theorem)
x^2=x^2/4+144
x^2-x^2=144
3x^2/4=144
3x^2=144*4
x^2=(144*4)/3
x^2=192(by solving)
x=2root43(root 43=6.557)
x=2*6.557
x=13.11
There fore,
perimeter = 13.11*3=39.34cm
area=root3/4*x^2
area=83.14(by solving)
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