Find the perimeter and area of Rhombus whose diagonals are 18 cm and 24 cm
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Answered by
2
Answer:
Step-by-step explanation:
perimeter is 20 and area is half into d1 into d2 that is 1/2*18*24=216
Answered by
5
Answer:
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Step-by-step explanation:
d1=18
d1/2=9
d2=24
d2/2=12
(a^2)=(d1/2)^2+(d2/2)^2
=9^2+12^2
=81+144
=225
a=15
peimter=4*side=4*15=60
area=(1/2)*d1*d2=(1/2)*18*24=24*9=216
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