find the perimeter and area of semicircle whose diameter is 56
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hey here is ur answer
d=2r = 56
r=56/2=28
perimeter = πr + d
=22/7 × 28 + 56
=22 × 4 + 56
=144
area = πr^2/2
=22/7×28×28×1/2
=1232 units sq
I hope this helps u
d=2r = 56
r=56/2=28
perimeter = πr + d
=22/7 × 28 + 56
=22 × 4 + 56
=144
area = πr^2/2
=22/7×28×28×1/2
=1232 units sq
I hope this helps u
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