Question

find the perimeter and area of square park of side 40.5m ​

Answer 1

${\large{\bf\dag\frak{\pmb{\underline{Digram}}}}}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large 40.5\ cm}\put(4.4,2){\bf\large 40.5\ cm}\end{picture}$

${\large{\bf\dag\frak{\pmb{\underline{Required~Solution}}}}}$

To find Perimeter :-

We know:

$\bigstar\boxed{\rm{Perimeter~of~square=4 \times side}}$

By using this formula we can find value of Perimeter of square

$\dashrightarrow\sf{}Perimeter~of~square=4 \times side$

$\dashrightarrow\sf{}Perimeter~of~square=4 \times 40.5$

$\dashrightarrow\sf{}Perimeter~of~square=4 \times \dfrac{405}{10}$

$\dashrightarrow\sf{}Perimeter~of~square=4 \times \dfrac{405}{5 \times 2}$

$\dashrightarrow\sf{}Perimeter~of~square=\cancel4 \times \dfrac{405}{5 \times \cancel2}$

$\dashrightarrow\sf{}Perimeter~of~square=2\times \dfrac{405}{5 }$

$\dashrightarrow\sf{}Perimeter~of~square=2\times \dfrac{\cancel{405}}{\cancel5 }$

$\dashrightarrow\sf{}Perimeter~of~square=2\times \dfrac{81}{1 }$

$\dashrightarrow\sf{}Perimeter~of~square=2 \times {81}$

$\dashrightarrow \underline{ \boxed{\sf{}Perimeter~of~square=162}}$

To find rectangle:

we know

$\bigstar\boxed{\rm{Area~of~square = {side}^{2} }}$

By using this formula we can find areas of square

$\dashrightarrow\sf{Area~of~square = {side}^{2}}$

$\dashrightarrow\sf{Area~of~square = {(40.5)}^{2}}$

$\dashrightarrow\sf{Area~of~square = {40.5 \times 40.5}}$

$\dashrightarrow \underline{ \boxed{\sf{Area~of~square = {1640.25}}}}$

Answer 2

refer to the attachment