Question

. Find the perimeter and area of the following squares whose dimensions are: (a) 16 cm (b) 5.3 m​

Answer 1

Answer:

perimeter of square= 4s

area of square= s^2

a) side = 16cm

perimeter= 64cm

area = 256cm^2

b) side = 5.3m

perimeter= 21.2m

area = 28.09m^2

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Answer 2

Answer:

(a) Hence the perimeter of a square is 64 cm and the area of a square is $256\;cm^{2} .$

(b) Hence the perimeter of a square is 21.2 m and the area of a square is $28.09\;m^{2} .$

Step-by-step explanation:

As per the data provided in the given question.

The given data is as follows,

(a) A side of a square (a) is 16 cm.

(b) A side of a square is (a) 5.3 cm.

We have to find the perimeter (P) and area of a square.

(a) At first we will calculate the perimeter of a square.

We will be using the formula of the perimeter of a square.

$P=4a$

Now we will substitute the value of (a) in the above formula.

[tex]P=4\times16\\ P=64\;cm[/tex]

Now we will calculate the area of a square.

We will be using the formula of the area of a square.

$A=a^{2}$

Now we will substitute the value of (a) in the above formula.

$A=16^{2}$

16 square we will write as 16 into 16.

[tex]A=16\times16\\ A=256\;cm^{2} [/tex]

Hence the perimeter of a square is 64 cm and the area of a square is $256\;cm^{2} .$

(b) At first we will calculate the perimeter of a square.

We will be using the formula of the perimeter of a square.

$P=4a$

Now we will substitute the value of (a) in the above formula.

[tex]P=4\times 5.3\\ P=21.2\;m[/tex]

Now we will calculate the area of a square.

We will be using the formula of the area of a square.

$A=a^{2}$

Now we will substitute the value of (a) in the above formula.

$A=5.3^{2}$

5.3 square we will write as 5.3 into 5.3.

[tex]A=5.3\times5.3\\ A=28.09\;m^{2} [/tex]

Hence the perimeter of a square is 21.2 m and the area of a square is $28.09\;m^{2} .$