Question

find the perimeter and area of the quadrilateral ABCD in which AB =21 CM angle BAC = 90 degree AC = 20 CM CD = 42 cm and AD = 34 CM ​

Answer 1

.ANSWER.

given :

AB = 21 cm

AD = 34 cm

CD = 42 cm

AC = 20 cm

BC = ?

•°• First , BC =

=> BC² = AC² + AB² [ Pythagorean theorem ]

=> BC² = 20² + 21²

=> BC = $\sqrt{20² + 21²}$

=> BC = 20 + 21

=> BC = 41 cm

•°• Perimeter of the quadrilateral =

=> AB + BC + CD + AD

=> 21 + 41 + 42 + 34

=> 138 cm

@Lily