Question

find the perimeter and area of the rectangle of the shortest side is 3 more than 2 times its shortest side

Answer 1

Let the shortest side be = a, then side b = 2·a and side c = (b + 24)

 

We are given that a + b + c = 84

 

Substituting for b and c

 

a + 2·a + (a + 24) = 84

 

4·a + 24 = 84

 

4·a = 84 - 24 = 60

 

a = 60/4 = 15 feet

 

b = 2·15 = 30 feet

 

c = 15 + 24 = 39 feet