Question

Find the perimeter and area of the rectangle whose length is 25 m and breadth 11 m 5 cm. answer fast

Answer 1

Answer:

area= l*b

area=25*11.05 (5 cm = 0.05 m)

area= 276.25

perimeter = 2(l+b)

perimeter= 2(25+11.05)

perimeter=2*36.05

perimter= 72.1

Step-by-step explanation:

Answer 2

We have

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• Length of the rectangle = 25 m
• Breadth of the rectangle = 11.05 m

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Solution

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$\: \: \: \: \: \: \: \: \bullet\bf\: \: \: {Formula\: used}$

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$\large{\boxed{\boxed{\bf{Perimeter_{(Rectangle)} = 2(l + b)}}}}$

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$\large{\boxed{\boxed{\bf{Area_{(Rectangle)} = l \times b}}}}$

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$\: \: \: \: \: \: \: \: \: \:\underline{\sf{\red{Finding\: Perimeter}}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\blue{Perimeter = 2(25 + 11.05)}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\blue{Perimeter = 2 \times 36.05}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\blue{Perimeter = 72.1\: m}}$

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$\: \: \: \: \: \: \: \: \: \:\underline{\sf{\red{Finding\: area}}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\blue{Area = 25 \times 11.05}}$

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$\tt:\implies\: \: \: \: \: \: \: \: {\blue{Area = 276.25\: m^2}}$

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$\underbrace{\underline{\sf{Hence}}}$

• Perimeter of the rectangle is 72.1 m
• Area of the rectangle is 276.25 m²

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