Question

Find the perimeter and area of the rectangles with the following lengths and breadth length =19m,breath=14m​

Answer 1

Given :

• Length $\leadsto$ 19m
• Breadth $\leadsto$ 14m

To find :

• We have to find the Perimeter and the Area of the Rectangle

Solution :

$\;\boxed{\sf{\blue{Area_{\:(rectangle)} = Length \times Breadth}}}$

$\;\boxed{\sf{\purple{Perimeter_{\:(rectangle)} = 2 \times Length + Breadth}}}$

$\therefore \: \: \: { \sf{ \underline{ First \: we \: will \: find \: the \: Perimeter}}} \\ \\ \\ : \implies \sf 2 \: \times (19m \: + \: 14m) \\ \\ \\ : \implies \sf 2 \: \times \: 33m \\ \\ \\ \: \: \: \: : \implies { \underline{ \boxed{ \pink{ \mathfrak{66 \: m}}}}} \\ \\ \\ \therefore \: \: \: \: \: \:{ \sf{ \underline{Now \: we \: will \: find \: the \: Area}}} \\ \\ \\ : \implies \sf 19m \: \times \: 14m \\ \\ \\ \: \: \: : \implies { \underline{ \boxed{ \pink{ \mathfrak{266 \: {m}^{2} }}}}}$

•°• Hence, verified! that the Perimeter is 66m and the Area is $\sf 266 {m}^{2}$

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Answer 2

Answer:

$\fbox\red{Question}$

Find the perimeter and area of the rectangles with the following lengths and breadth.

• Length = 19m
• Breadth = 14m

$\fbox\red{Given}$

• Length - 19m
• Breadth - 14m

$\fbox\red{To\:find}$

$\mapsto$We have to find the Perimeter and the Area of the Rectangle.

$\fbox\red{Solution}$

First we will take out the perimeter.

Formula for taking out perimeter of rectangle

• 2 ( l + b )

= 2 ( 19 + 14 )

= 38 + 28

= 66 m²

Now, we will take out Area.

Formula for taking out area of rectangle

• l × b

= 19 × 14

= 266 m²

•°• The perimeter of rectangle is $\fbox\purple{x\:=\:66m²}$

The area of rectangle is $\fbox\blue{x\:=\:266m²}$

$\fbox\red{Diagram:-}$

$\begin{gathered}\begin{gathered} \blue{\tt19 \: m} \: \: \: \: \: \: \: \: \: \: \: \\ \pink{\boxed{\begin{array}{}\bf { \red{}}\\{\qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:}{}\\ { \sf{ }}\\ { \sf{ }} \\ \\ { \sf{ }}\end{array}}} \blue{ \tt \:14 \: m} \end{gathered}\end{gathered}$